发布: coolker
最近两天在看圆周率的算法,网上流传这么一个经典的算法,
#include < stdio.h >
long a = 10000 ,b = 0 ,c = 2800 ,d,e,f[ 2801 ],g;
void main()
{
printf( " %d " ,b);
for (;b != c;)
{
f[b] = a / 5 ;
b ++ ;
}
for (; d = 0 ,g = c * 2 ; c -= 14 ,printf( " %.4d " ,e + d / a),e = d % a)
...
